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(C) To solve $(729)^{\frac{1}{3}}$,we find the prime factorization of $729$.$729 = 3 	imes 3 	imes 3 	imes 3 	imes 3 	imes 3 = 3^6$.Alternatively

Vedclass · Accepted Answer

$9$

Vedclass · Answer

(C) To solve $(729)^{\frac{1}{3}}$,we find the prime factorization of $729$.$729 = 3 	imes 3 	imes 3 	imes 3 	imes 3 	imes 3 = 3^6$.Alternatively,$729 = 9 	imes 9 	imes 9 = 9^3$.Therefore,$(729)^{\frac{1}{3}} = (9^3)^{\frac{1}{3}}$.Using the exponent rule $(a^m)^n = a^{m 	imes n}$,we get $9^{3 	imes \frac{1}{3}} = 9^1 = 9$.

Fill in the blank to make the following statement true:
$(729)^{\frac{1}{3}} = \ldots$

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Fill in the blank to make the following statement true:$(729)^{\frac{1}{3}} = \ldots$