Figure shows a rod ${AB}$, which is bent in a $120^{\circ}$ circular arc of radius $R$. A charge $(-Q)$ is uniformly distributed over rod ${AB}$. What is the electric field $\overrightarrow{{E}}$ at the centre of curvature ${O}$ ?
Figure shows a rod ${AB}$, which is bent in a $120^{\circ}$ circular arc of radius $R$. A charge $(-Q)$ is uniformly distributed over rod ${AB}$. What is the electric field $\overrightarrow{{E}}$ at the centre of curvature ${O}$ ?
- [JEE MAIN 2021]
- A
$\frac{3 \sqrt{3} {Q}}{8 \pi \varepsilon_{0} {R}^{2}}(\hat{{i}})$
- B
$\frac{3 \sqrt{3} Q}{8 \pi^{2} \varepsilon_{0} R^{2}}(\hat{i})$
- C
$\frac{3 \sqrt{3} Q}{16 \pi^{2} \varepsilon_{0} R^{2}}(\hat{i})$
- D
$\frac{3 \sqrt{3} Q}{8 \pi^{2} \varepsilon_{0} R^{2}}(-\hat{i})$
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