Five point charge each having magnitude $‘q’$ are placed at the corner of hexagon as shown in fig. Net electric field at the centre $‘O’$ is $\vec E$. To get net electric field at $‘O’$ be $6\vec E$, charge placed on the remaining sixth corner should be

115-748

  • A

    $6\, q$

  • B

    $-6\, q$

  • C

    $5\, q$

  • D

    $-5\, q$

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