Factorise 4 x^{2}+9 y^{2}+49 z^{2}-12 x y+42 | vedclass

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Question

(A) We use the algebraic identity: $(a+b+c)^2 = a^2 + b^2 + c^2 + 2ab + 2bc + 2ca$.Given expression: $4x^2 + 9y^2 + 49z^2 - 12xy + 42yz - 28zx$.This c

Vedclass · Accepted Answer

$(2x - 3y - 7z)^2$

Vedclass · Answer

(A) We use the algebraic identity: $(a+b+c)^2 = a^2 + b^2 + c^2 + 2ab + 2bc + 2ca$.Given expression: $4x^2 + 9y^2 + 49z^2 - 12xy + 42yz - 28zx$.This can be written as: $(2x)^2 + (-3y)^2 + (-7z)^2 + 2(2x)(-3y) + 2(-3y)(-7z) + 2(-7z)(2x)$.Here,$a = 2x$,$b = -3y$,and $c = -7z$.Therefore,the expression is equal to $(2x - 3y - 7z)^2$,which is $(2x - 3y - 7z)(2x - 3y - 7z)$.

Factorise $4 x^{2}+9 y^{2}+49 z^{2}-12 x y+42 y z-28 z x$.

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