Expand the following:
$\left(4-\frac{1}{3 x}\right)^{3}$
Expand the following:
$\left(4-\frac{1}{3 x}\right)^{3}$
We have,
$\left(4-\frac{1}{3 x}\right)^{3}=(4)^{3}-\left(\frac{1}{3 x}\right)^{3}-3(4)\left(\frac{1}{3 x}\right)\left(4-\frac{1}{3 x}\right)$
$\left[\because(a-b)^{3}=a^{3}-b^{3}-3 a b(a-b)\right]$
$=64-\frac{1}{27 x^{3}}-\frac{4}{x}\left(4-\frac{1}{3 x}\right)$
$=64-\frac{1}{27 x^{3}}-\frac{16}{x}+\frac{4}{3 x^{2}}$
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