Explain the basic nuclear process by equation in $\beta -$ decay. 

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Although the nucleus does not contain electrons, positrons or neutrons, although they emit these particles.

In a unstable nucleus which contains a extra neutron so for its stability a neutron is converted into proton which can be represented by the following equation.

$n \rightarrow p+\bar{e}+\bar{v}$ This is called $\beta^{-}$decay.

In a unstable nucleus which contains a extra proton, so for its stability a extra proton is converted into neutron which can be represent by the following equation.

$p \rightarrow n+e^{+}+v$ This is called $\beta^{+}$-decay.

Note that while a free neutron decays to proton, the decay of proton to neutron is possible only inside the nucleus, since proton has smaller mass than neutron, therefore decay of proton is not possible.

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