The nucleus $_{48}^{115}Cd$ after two successive ${\beta ^ - }$ decays will give
$_{46}^{115}Pa$
$_{49}^{114}In$
$_{50}^{113}Sn$
$_{50}^{115}Sn$
A nuclear reaction given by $_Z{X^A}\, \to {\,_{Z + 1}}{Y^A}{ + _{ - 1}}{e^0} + \bar p$ represents
A radioactive nucleus undergoes a series of decay according to the scheme
$A\xrightarrow{\alpha }{{A}_{1}}\xrightarrow{\beta }{{A}_{2}}\xrightarrow{\alpha }{{A}_{3}}\xrightarrow{\gamma }{{A}_{4}}$
If the mass number and atomic number of $A$ are $180$ and $72$ respectively, then what are these number for $A_4$
During a negative beta decay
A plot of the number of neutrons $(N)$ against the number of protons ( $P$ )of stable nuclei exhibits upward deviation from linearity for atomic number, $Z>20$. For an unstable nucleus having $N / P$ ratio less than $1$ , the possible mode($s$) of decay is(are)
($A$) $\beta^{-}$-decay ( $\beta$ emission)
($B$) orbital or $K$-electron sasture
($C$) neutron emission
($D$) $\beta^{+}$-decay (positron emission)
Beta rays emitted by a radioactive material are