Explain subtraction of vectors.

Vedclass pdf generator app on play store
Vedclass iOS app on app store

Subtraction of vectors can be defined in terms of addition of vectors.

We define the difference of two vectors $\overrightarrow{\mathrm{A}}$ and $\overrightarrow{\mathrm{B}}$ as the sum of two vectors $\overrightarrow{\mathrm{A}}$ and $-\overrightarrow{\mathrm{B}}$.

$\overrightarrow{\mathrm{A}}-\overrightarrow{\mathrm{B}}=\overrightarrow{\mathrm{A}}+(-\overrightarrow{\mathrm{B}})$

Thus, substraction of vectors means adding opposite of a vector in another vector.

In figure (a), $\vec{A}, \vec{B}$ and $-\vec{B}$ is represented.

In figure (b), $-\vec{B}$ is added to $\vec{A}$.

By triangle method for vector addition,

$\overrightarrow{\mathrm{R}_{2}}=\overrightarrow{\mathrm{A}}+(-\overrightarrow{\mathrm{B}})$

$\therefore\overrightarrow{\mathrm{R}_{2}}=\overrightarrow{\mathrm{A}}-\overrightarrow{\mathrm{B}}$

(For comparison, $\overrightarrow{\mathrm{R}_{1}}=\overrightarrow{\mathrm{A}}+\overrightarrow{\mathrm{B}}$ is shown).

885-s60

Similar Questions

Two forces ${F_1} = 1\,N$ and ${F_2} = 2\,N$ act along the lines $x = 0$ and $y = 0$ respectively. Then the resultant of forces would be

If the sum of two unit vectors is a unit vector, then magnitude of difference is

If $P + Q = R$ and $| P |=| Q |=\sqrt{3}$ and $| R |=3$, then the angle between $P$ and $Q$ is

The resultant of two vectors at an angle $150^{\circ}$ is $10$ units and is perpendicular to one vector. The magnitude of the smaller vector is ....... units

If the magnitude of sum of two vectors is equal to the magnitude of difference of the two vectors, the angle between these vectors is ........ $^o$

  • [NEET 2016]