If P + Q = R and |P| = |Q| = sqrt{3} and |R| | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The magnitude of the resultant vector $R$ is given by the formula: $|R| = \sqrt{|P|^2 + |Q|^2 + 2|P||Q| \cos 	heta}$,where $	heta$ is the angle

Vedclass · Accepted Answer

$\pi / 3$

Vedclass · Answer

(C) The magnitude of the resultant vector $R$ is given by the formula: $|R| = \sqrt{|P|^2 + |Q|^2 + 2|P||Q| \cos 	heta}$,where $	heta$ is the angle between vectors $P$ and $Q$.Given $|P| = |Q| = \sqrt{3}$ and $|R| = 3$.Substituting the values into the formula:$3 = \sqrt{(\sqrt{3})^2 + (\sqrt{3})^2 + 2(\sqrt{3})(\sqrt{3}) \cos 	heta}$$3 = \sqrt{3 + 3 + 6 \cos 	heta}$Squaring both sides:$9 = 6 + 6 \cos 	heta$$3 = 6 \cos 	heta$$\cos 	heta = 3 / 6 = 1 / 2$Since $\cos 	heta = 1 / 2$,the angle $	heta = 60^{\circ}$ or $\pi / 3$ radians.

If $P + Q = R$ and $|P| = |Q| = \sqrt{3}$ and $|R| = 3$,then the angle between $P$ and $Q$ is

Similar Questions

Which pair of the following forces will never give a resultant force of $2 \, N$?

At what angle do two forces $(x + y)$ and $(x - y)$ act so that their resultant is $\sqrt{x^2 + y^2}$?

In the diagram shown in the figure,which of the following relations is correct?

What should be the angle $\theta$ between two vectors $\vec{A}$ and $\vec{B}$ so that the magnitude of the resultant vector is minimum (in $^{\circ}$)?

What is the minimum number of vectors of equal magnitude required to produce a zero resultant vector?

Vedclass Test Series

Exam Paper Generator

Online Exam Module