The resultant of two vectors at an angle 150^ | vedclass

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Question

(b)

$\Rightarrow R^2+A^2=B^2 \ldots (1)$

$R=10$

Also $	an 30^{\circ}=\frac{	ext { Perpendicular }}{	ext { Base }}$

$\frac{1}{\sqrt{3}}=

Vedclass · Accepted Answer

$10 \sqrt{3}$

Vedclass · Answer

(b)

$\Rightarrow R^2+A^2=B^2 \ldots (1)$

$R=10$

Also $	an 30^{\circ}=\frac{	ext { Perpendicular }}{	ext { Base }}$

$\frac{1}{\sqrt{3}}=\frac{R}{A}$

From equation $(1)$ $A=10 \sqrt{3}$

$(10)^2+(10 \sqrt{3})^2=B^2$

$B=20$

The resultant of two vectors at an angle $150^{\circ}$ is $10$ units and is perpendicular to one vector. The magnitude of the smaller vector is ....... units

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