(D) We know that $\tan(90^{\circ} - \theta) = \cot \theta$.Given expression: $\frac{\tan 26^{\circ}}{\cot 64^{\circ}}$.We can write $\tan 26^{\circ}$

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(D) We know that $\tan(90^{\circ} - \theta) = \cot \theta$.Given expression: $\frac{\tan 26^{\circ}}{\cot 64^{\circ}}$.We can write $\tan 26^{\circ}$ as $\tan(90^{\circ} - 64^{\circ})$.Since $\tan(90^{\circ} - 64^{\circ}) = \cot 64^{\circ}$,the expression becomes:$\frac{\cot 64^{\circ}}{\cot 64^{\circ}} = 1$.

Class 10 Mathematics Introduction to Trigonometry Textbook - Introduction to Trigonometry

Easy

Evaluate:
$\frac{\tan 26^{\circ}}{\cot 64^{\circ}}$

A
$-1$
B
$0$
C
$2.5$
D
$1$

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Introduction to Trigonometry

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Textbook - Introduction to Trigonometry

State whether the following is true or false. Justify your answer.
$\cot A$ is not defined for $A = 0^{\circ}$.

Easy

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If $\angle B$ and $\angle Q$ are acute angles such that $\sin B = \sin Q$,then prove that $\angle B = \angle Q$.

Easy

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Prove that $\sec A(1-\sin A)(\sec A+\tan A)=1$.

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In $\triangle PQR$, right-angled at $Q$, $PR + QR = 25 \, cm$ and $PQ = 5 \, cm$. Determine the values of $\sin P, \cos P$ and $\tan P$.

Medium

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If $\cot \theta = \frac{7}{8},$ evaluate:
$(i) \frac{(1+\sin \theta)(1-\sin \theta)}{(1+\cos \theta)(1-\cos \theta)}$
$(ii) \cot^2 \theta$

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Evaluate:$\frac{\tan 26^{\circ}}{\cot 64^{\circ}}$

Similar Questions

State whether the following is true or false. Justify your answer.$\cot A$ is not defined for $A = 0^{\circ}$.

If $\angle B$ and $\angle Q$ are acute angles such that $\sin B = \sin Q$,then prove that $\angle B = \angle Q$.

Prove that $\sec A(1-\sin A)(\sec A+\tan A)=1$.

In $\triangle PQR$, right-angled at $Q$, $PR + QR = 25 \, cm$ and $PQ = 5 \, cm$. Determine the values of $\sin P, \cos P$ and $\tan P$.

If $\cot \theta = \frac{7}{8},$ evaluate:$(i) \frac{(1+\sin \theta)(1-\sin \theta)}{(1+\cos \theta)(1-\cos \theta)}$$(ii) \cot^2 \theta$

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Evaluate:
$\frac{\tan 26^{\circ}}{\cot 64^{\circ}}$

State whether the following is true or false. Justify your answer.
$\cot A$ is not defined for $A = 0^{\circ}$.

If $\cot \theta = \frac{7}{8},$ evaluate:
$(i) \frac{(1+\sin \theta)(1-\sin \theta)}{(1+\cos \theta)(1-\cos \theta)}$
$(ii) \cot^2 \theta$