The displacement equation for a particle is $s = 3t^3 + 7t^2 + 14t + 8 \ m$. Its acceleration at time $t = 1 \ s$ is ....... $m/s^2$.

The relation between the displacement $x$ (in metre) and the time $t$ (in second) of a particle is $t = 2x^2 + 3x$. If the displacement of the particle is $25 \ cm$ from the origin $(x = 0)$,then the acceleration of the particle is:

$A$ body is moving according to the equation $x = at + bt^2 - ct^3$,where $x$ is displacement and $a, b,$ and $c$ are constants. The acceleration of the body is:

The correct position $(x)$ - time $(t)$ graph for a particle moving with negative acceleration is

$A$ particle starts from rest. Its acceleration $a$ versus time $t$ is shown in the figure. The maximum speed of the particle will be (in $m/s$)

If the displacement ($s$ in metre) of a moving particle in terms of time ($t$ in second) is $s = t^3 - 6t^2 + 18t + 9$,then the minimum velocity attained by the particle is (in $m \ s^{-1}$)