A body is moving according to the equation x | vedclass

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(C) The displacement of the body is given by the equation: $x = at + bt^2 - ct^3$.To find the velocity $(v)$,we differentiate the displacement with re

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$2b - 6ct$

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(C) The displacement of the body is given by the equation: $x = at + bt^2 - ct^3$.To find the velocity $(v)$,we differentiate the displacement with respect to time $(t)$:$v = \frac{dx}{dt} = \frac{d}{dt}(at + bt^2 - ct^3) = a + 2bt - 3ct^2$.To find the acceleration $(a_{acc})$,we differentiate the velocity with respect to time $(t)$:$a_{acc} = \frac{dv}{dt} = \frac{d}{dt}(a + 2bt - 3ct^2) = 0 + 2b - 6ct$.Therefore,the acceleration of the body is $2b - 6ct$.

$A$ body is moving according to the equation $x = at + bt^2 - ct^3$,where $x$ is displacement and $a, b,$ and $c$ are constants. The acceleration of the body is:

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