Draw electric field lines for simple charge distributions.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The concept of electric field lines was introduced by Faraday to visualize electric fields around charged configurations. Faraday referred to them as lines of force.
The figures illustrate the field lines around various simple charge configurations. Although the figures represent them in a $2$-dimensional plane,these field lines actually exist in $3$-dimensional space.
$1$. For a positive point charge $(q > 0)$,field lines point radially outward.
$2$. For a negative point charge $(q < 0)$,field lines point radially inward.
$3$. For two positive charges,the field lines repel each other.
$4$. For an electric dipole (positive and negative charge),field lines originate from the positive charge and terminate at the negative charge.
$5$. For two negative charges,the field lines are similar to two positive charges but with arrows pointing inward.
$6$. For a uniform electric field,the field lines are parallel and equidistant.
$7$. When a metallic sphere is placed in a uniform electric field,the field lines are perpendicular to the surface of the conductor and do not penetrate it.
$8$. When a dielectric slab is placed in a uniform electric field,the field lines pass through it but are modified due to polarization.

Explore More

Similar Questions

$A$ square surface of side $L \; m$ in the plane of the paper is placed in a uniform electric field $E \; (V/m)$ acting along the same plane at an angle $\theta$ with the horizontal side of the square as shown in the figure. The electric flux linked to the surface,in units of $V \cdot m$,is:

If a charge $q$ is placed at the centre of the flat surface of a closed hemispherical non-conducting surface,what is the total electric flux passing through the flat surface?

The electric field in a region is given by $\overrightarrow{E} = \frac{2}{5} E_{0} \hat{i} + \frac{3}{5} E_{0} \hat{j}$ with $E_{0} = 4.0 \times 10^{3} \, N/C$. The flux of this field through a rectangular surface area $0.4 \, m^{2}$ parallel to the $Y-Z$ plane is ....... $N m^{2} C^{-1}$.

What is the net flux of the uniform electric field of $E = 3 \times 10^{3} \hat{i} \; N/C$ through a cube of side $20 \; cm$ oriented so that its faces are parallel to the coordinate planes?

$A$ point charge $q$ is placed at the corner of a cube of side $a$ as shown in the figure. What is the electric flux through the face $ABCD$?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo