It is not convenient to use a spherical Gauss | vedclass

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Question

(B) Gauss's law is most effective when the charge distribution possesses high degrees of symmetry (such as spherical,cylindrical,or planar symmetry).

Vedclass · Accepted Answer

This problem does not have spherical symmetry

Vedclass · Answer

(B) Gauss's law is most effective when the charge distribution possesses high degrees of symmetry (such as spherical,cylindrical,or planar symmetry). For an electric dipole,the electric field does not possess spherical symmetry because the field depends on the orientation relative to the dipole axis. Since the electric field magnitude is not constant over a spherical surface centered at the dipole,the integral $\oint \vec{E} \cdot d\vec{A}$ cannot be simplified to $E \oint dA$. Therefore,it is not convenient to use a spherical Gaussian surface for this calculation.

It is not convenient to use a spherical Gaussian surface to find the electric field due to an electric dipole using Gauss's theorem because

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