Consider the species CH_4,NH_4^+ and BH_4^-. | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $1$. Calculate the total number of electrons in each species:$CH_4$: $6 + 4(1) = 10$ electrons.$NH_4^+$: $7 + 4(1) - 1 = 10$ electrons.$BH_4^-$: $

Vedclass · Accepted Answer

They are isoelectronic and all have tetrahedral structures

Vedclass · Answer

(B) $1$. Calculate the total number of electrons in each species:$CH_4$: $6 + 4(1) = 10$ electrons.$NH_4^+$: $7 + 4(1) - 1 = 10$ electrons.$BH_4^-$: $5 + 4(1) + 1 = 10$ electrons.Since all species have $10$ electrons,they are isoelectronic.$2$. Determine the geometry:All three species have a central atom bonded to $4$ hydrogen atoms with no lone pairs on the central atom. According to $VSEPR$ theory,they all exhibit $sp^3$ hybridization and possess a tetrahedral geometry.

Consider the species $CH_4$,$NH_4^+$ and $BH_4^-$. Choose the correct option with respect to these species.

Similar Questions

The numbers of lone pair$(s)$ on $Xe$ in $XeF_2$ and $XeF_4$ are,respectively:

In which of the following covalent compounds is the bond angle maximum?

In which of the following molecules are all bond lengths the same?

In the following three-dimensional structure of $CH_4$,the bonds are labelled as $W, X, Y$ and $Z$. The bonds projecting out of the plane are:

Which of the following has a trigonal bipyramidal shape?

Vedclass Test Series

Exam Paper Generator

Online Exam Module