Assertion : B_2 molecule is diamagnetic.
Rea | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$B_2$ molecule has no of electrons $= 10$

Molecular orbital configuration
$\sigma {\left( {1s} \right)^2}\,{\sigma ^*}{\left( {1s} \right)^2}\,\si

Vedclass · Accepted Answer

If both the Assertion and Reason are incorrect.

Vedclass · Answer

$B_2$ molecule has no of electrons $= 10$

Molecular orbital configuration
$\sigma {\left( {1s} \right)^2}\,{\sigma ^*}{\left( {1s} \right)^2}\,\sigma {\left( {2s} \right)^2}\,{\sigma ^*}{(2s)^2}\,\pi 2p_x^1\,\pi 2p_y^1$
Due to unpaired electron, it is paramagnetic. The highest occupied $MO$ is of $\pi -$ type.

Assertion : $B_2$ molecule is diamagnetic.
Reason : The highest occupied molecular orbital is of $\sigma $ type.

Similar Questions

Give electron configuration, Magnetic property, bond order and energy diagram for carbon $\left( {{{\rm{C}}_2}} \right)$.

Which of the following is paramagnetic

The total number of anti bonding molecular orbitals, formed from $2 \mathrm{~s}$ and $2 \mathrm{p}$ atomic orbitals in a diatomic molecule is_______

What is the number of unpaired electron(s) in the highest occupied molecular orbital of the following species : $N _2: N _2^{+} ; O _2 ; O _2^{+}$?

If the magnetic moment of a dioxygen species is $1.73 \;B.M$, it may be

Assertion : $B_2$ molecule is diamagnetic. Reason : The highest occupied molecular orbital is of $\sigma $ type.