Assertion : B_2 molecule is diamagnetic. Reas | vedclass

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Question

(D) The total number of electrons in a $B_2$ molecule is $10$. The molecular orbital configuration is $\sigma(1s)^2 \sigma^*(1s)^2 \sigma(2s)^2 \sigma

Vedclass · Accepted Answer

If both the Assertion and Reason are incorrect.

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(D) The total number of electrons in a $B_2$ molecule is $10$. The molecular orbital configuration is $\sigma(1s)^2 \sigma^*(1s)^2 \sigma(2s)^2 \sigma^*(2s)^2 \pi 2p_x^1 \pi 2p_y^1$. Due to the presence of two unpaired electrons in the $\pi 2p$ orbitals,the $B_2$ molecule is paramagnetic. The highest occupied molecular orbital $(HOMO)$ is of $\pi$ type,not $\sigma$ type. Therefore,both the Assertion and the Reason are incorrect.

Assertion : $B_2$ molecule is diamagnetic. Reason : The highest occupied molecular orbital is of $\sigma$ type.

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