The correct order of energies of molecular orbitals of $N _2$ molecule, is
The correct order of energies of molecular orbitals of $N _2$ molecule, is
- [NEET 2023]
- A
$\sigma 1 s < \sigma^* 1 s < \sigma 2 s < \sigma^* 2 s < \left(\pi 2 p_{ x }=\pi 2 p_{ y }\right) < \left(\pi^* 2 p_{ x }=\pi^* 2 p_{ y }\right) < \sigma 2 p_{ z } < \sigma^* 2 p_{ z }$
- B
$\sigma 1 s < \sigma^* 1 s < \sigma 2 s < \sigma^* 2 s < \left(\pi 2 p_{ x }=\pi 2 p_{ y }\right) < \sigma 2 p_{ z } < \left(\pi^* 2 p_{ x }=\pi^* 2 p_{ y }\right) < \sigma^* 2 p_{ z }$
- C
$\sigma 1 s < \sigma^* 1 s < \sigma 2 s < \sigma^* 2 s < \sigma 2 p_{ z } < \left(\pi 2 p_{ x }=\pi 2 p_{ y }\right) < \left(\pi^* 2 p_{ x }=\pi^* 2 p_{ y }\right) < \sigma^* 2 p_{ z }$
- D
$\sigma 1 s < \sigma^* 1 s < \sigma 2 s < \sigma^* 2 s < \sigma 2 p_{ z } < \sigma^* 2 p_{ z } < \left(\pi 2 p_{ x }=\pi 2 p_{ y }\right) < \left(\pi^* 2 p_{ x }=\pi^* 2 p_{ y }\right)$
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Thermal decomposition of $AgNO _3$ produces two paramagnetic gases. The total number of electrons present in the antibonding molecular orbitals of the gas that has the higher number of unpaired electrons is. . . . .
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- [IIT 2022]
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