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(A) According to the First Law of Thermodynamics,$Q = \Delta U + W$.For an isobaric process (constant pressure),the heat supplied is $Q = n C_p \Delta

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$\frac{\gamma - 1}{\gamma}$

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(A) According to the First Law of Thermodynamics,$Q = \Delta U + W$.For an isobaric process (constant pressure),the heat supplied is $Q = n C_p \Delta T$.The work done is $W = P \Delta V = n R \Delta T$.The change in internal energy is $\Delta U = n C_v \Delta T$.The fraction of heat converted into work is $\frac{W}{Q} = \frac{n R \Delta T}{n C_p \Delta T} = \frac{R}{C_p}$.Since $C_p = \frac{\gamma R}{\gamma - 1}$,we substitute this into the expression:$\frac{W}{Q} = \frac{R}{\frac{\gamma R}{\gamma - 1}} = \frac{\gamma - 1}{\gamma}$.

At constant pressure,what fraction of the heat supplied to an ideal gas is converted into mechanical work?

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