The work done to double the volume of $0.1 \ mol$ of a gas at constant pressure and a temperature of $27 \ ^\circ C$ is equal to ..... $cal$.

  • A
    $54$
  • B
    $600$
  • C
    $60$
  • D
    $546$

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Derive the expression for work done by a gas during an isobaric process (constant pressure).

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$10 \text{ mole}$ of an ideal gas is undergoing the process shown in the figure. The heat involved in the process from $P_1$ to $P_2$ at constant volume $V = 1 \text{ m}^3$ is $\alpha \text{ Joule}$ ($P_1 = 21.7 \text{ Pa}$,$P_2 = 30 \text{ Pa}$,$C_v = 21 \text{ J/K} \cdot \text{mol}$,$R = 8.3 \text{ J/mol} \cdot \text{K}$). The value of $\alpha$ is . . . . . . .

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