A monoatomic ideal gas is heated at constant | vedclass

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(D) For a monoatomic gas,the degrees of freedom $f = 3$.At constant pressure,the molar heat capacity is $C_P = \frac{5}{2}R$ and the molar heat capaci

Vedclass · Accepted Answer

$60$

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(D) For a monoatomic gas,the degrees of freedom $f = 3$.At constant pressure,the molar heat capacity is $C_P = \frac{5}{2}R$ and the molar heat capacity at constant volume is $C_V = \frac{3}{2}R$.The total heat supplied is $\Delta Q = n C_P \Delta T$.The change in internal energy is $\Delta U = n C_V \Delta T$.The fraction of heat used to change internal energy is $\frac{\Delta U}{\Delta Q} = \frac{n C_V \Delta T}{n C_P \Delta T} = \frac{C_V}{C_P}$.Substituting the values,$\frac{\Delta U}{\Delta Q} = \frac{\frac{3}{2}R}{\frac{5}{2}R} = \frac{3}{5} = 0.6$.Therefore,the percentage of total heat used is $0.6 	imes 100 = 60 \%$.

$A$ monoatomic ideal gas is heated at constant pressure. The percentage of total heat used in changing the internal energy is (in $\%$)

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