Which of the following is paramagnetic?

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The electronic configuration of $O_2$ ($16$ electrons) according to Molecular Orbital Theory is:$O_2 = \sigma(1s)^2 \sigma^*(1s)^2 \sigma(2s)^2 \s

Vedclass · Accepted Answer

$O_2$

Vedclass · Answer

(A) The electronic configuration of $O_2$ ($16$ electrons) according to Molecular Orbital Theory is:$O_2 = \sigma(1s)^2 \sigma^*(1s)^2 \sigma(2s)^2 \sigma^*(2s)^2 \sigma(2p_z)^2 \pi(2p_x)^2 = \pi(2p_y)^2 \pi^*(2p_x)^1 = \pi^*(2p_y)^1$Since the molecule contains two unpaired electrons in the antibonding $\pi^*$ orbitals,it exhibits paramagnetic behavior.In contrast,$CN^-$,$CO$,and $NO^+$ are all isoelectronic with $14$ electrons and have no unpaired electrons,making them diamagnetic.

Similar Questions

What is considered a species?

If $lx^2+3xy-2y^2-5x+5y+k=0$ represents a pair of perpendicular lines,then

The value of '$a$' for which the three given planes
$P_1: (a+1)x - y - z = a$
$P_2: x - (a+1)y - z = a$
$P_3: x - y - (a+1)z = a$
have no point in common,is

Which of the following statements is correct?

In an experiment with a beam balance,an unknown mass $m$ is balanced by two known masses of $16\,kg$ and $4\,kg$ as shown in the figure. The value of the unknown mass $m$ is ......... $kg$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module