As shown in the figure. a configuration of tw | vedclass

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Question

For equilibrium along the plane

$mg \sin 	heta=\frac{1}{4 \pi \epsilon_0} 	imes \frac{ q _0^2}{\left( h \operatorname{cosec} 30^{\circ}ight)^2}

Vedclass · Accepted Answer

$300$

Vedclass · Answer

For equilibrium along the plane

$mg \sin 	heta=\frac{1}{4 \pi \epsilon_0} 	imes \frac{ q _0^2}{\left( h \operatorname{cosec} 30^{\circ}ight)^2}$

$	herefore h ^2=\frac{1}{4 \pi \epsilon_0} 	imes \frac{ q _0^2}{ mg \operatorname{cosec} 30^{\circ}}$

$=9 	imes 10^9 	imes \frac{\left(2 	imes 10^{-6}ight)^2}{0.02 	imes 10 	imes 2}$

$	herefore h =3 	imes 10^4 	imes \frac{2 	imes 10^{-6}}{0.2}$

$=0.3\,m$

$=300\,mm$

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