$A$ uniform thin rod of length $2L$ and mass $m$ lies on a horizontal table. $A$ horizontal impulse $J$ is given to the rod at one end. There is no friction. The total kinetic energy of the rod just after the impulse will be

  • A
    $\frac{J^2}{2m}$
  • B
    $\frac{J^2}{m}$
  • C
    $\frac{2J^2}{m}$
  • D
    $\frac{6J^2}{m}$

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