An unbiased coin is tossed 8 times. The proba | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The total number of outcomes when a coin is tossed $8$ times is $2^8 = 256$. The event of obtaining at least one head and at least one tail is the

Vedclass · Accepted Answer

$\frac{127}{128}$

Vedclass · Answer

(B) The total number of outcomes when a coin is tossed $8$ times is $2^8 = 256$. The event of obtaining at least one head and at least one tail is the complement of the event of obtaining all heads or all tails. $P(	ext{All Heads}) = \frac{1}{2^8} = \frac{1}{256}$. $P(	ext{All Tails}) = \frac{1}{2^8} = \frac{1}{256}$. The probability of obtaining either all heads or all tails is $P(	ext{All Heads}) + P(	ext{All Tails}) = \frac{1}{256} + \frac{1}{256} = \frac{2}{256} = \frac{1}{128}$. Therefore,the required probability is $1 - \frac{1}{128} = \frac{127}{128}$.

An unbiased coin is tossed $8$ times. The probability of obtaining at least one head and at least one tail is

Similar Questions

In a Binomial distribution $B(n, p)$,the sum and product of the mean and the variance are $5$ and $6$ respectively,then $6(n+p-q)=$

Let $X$ be a random variable having binomial distribution $B(7, p)$. If $P(X=3) = 5P(X=4)$,then the sum of the mean and the variance of $X$ is

An experiment succeeds twice as often as it fails. Then the probability,that in the next $6$ trials there will be at least $4$ successes,is

Let $X$ be a random variable having a Binomial distribution $B(7, p)$. If $P(X=3) = 5 P(X=4)$,then the variance of $X$ is:

If the mean and variance of a binomial variate $X$ are $2$ and $1$ respectively,then the probability that $X$ takes a value greater than $1$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module