In a Binomial distribution $B(n, p)$,the sum and product of the mean and the variance are $5$ and $6$ respectively,then $6(n+p-q)=$

When two dice are rolled,let $x$ be the probability that the sum of the numbers appearing on the dice is at most $7$. Let $y$ be the probability of getting a sum of $7$ at least once when a pair of dice are rolled $n$ times. In order to have $y > x$,the minimum value of $n$ is

If $X \sim B(7, p)$ is a binomial variate and $P(X=3)=P(X=5)$ then $p=$

If $15$ coins are tossed,then the probability of getting $10$ heads is:

$A$ dice is thrown $(2n + 1)$ times. The probability of getting $1, 3$ or $4$ at most $n$ times is:

$A$ box contains $30$ toys of the same size,in which $10$ toys are white and the remaining toys are blue. $A$ toy is drawn at random from the box and it is replaced in the box after noting down its colour. If $5$ toys are drawn in this way,then the probability of getting at most $2$ white toys is