$A$ transverse pulse generated at the bottom of a uniform rope of length $L$ travels in an upward direction. The time taken by it to travel the full length of the rope will be

  • A
    $\sqrt{\frac{L}{2g}}$
  • B
    $\sqrt{\frac{2L}{g}}$
  • C
    $\sqrt{\frac{L}{g}}$
  • D
    $\sqrt{\frac{4L}{g}}$

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Similar Questions

$A$ uniform metal wire has length $L$,mass $M$,and density $\rho$. It is under tension $T$,and $v$ is the speed of a transverse wave along the wire. The area of cross-section of the wire is:

When the length of a tense wire is made half while keeping its mass constant,what will be the effect on the speed of the transverse wave in it?

$A$ transverse wave travels on a taut steel wire with a velocity of $v$ when the tension in it is $2.06 \times 10^{4} \; N$. When the tension is changed to $T$,the velocity changes to $v/2$. The value of $T$ is close to:

Which of the following is an example of a transverse wave?

$A$ composite string is made up by joining two strings of different mass per unit length,$\mu$ and $4\mu$. The composite string is under the same tension $T$. $A$ transverse wave pulse,$Y = (6 \text{ mm}) \sin(5t + 40x)$,where $t$ is in seconds and $x$ is in meters,is sent along the lighter string towards the joint. The joint is at $x = 0$. The equation of the wave pulse reflected from the joint is:

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