A steady current I goes through a wire loop m | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

Using the concept of area of triangle

$\frac{1}{2} xPD X _5 x =\frac{1}{2} x _{3 x } X 4 x$

$	herefore PD =\frac{12 x }{5}$

$QD =\sqrt{( PQ

Vedclass · Accepted Answer

$7$

Vedclass · Answer

Using the concept of area of triangle

$\frac{1}{2} xPD X _5 x =\frac{1}{2} x _{3 x } X 4 x$

$	herefore PD =\frac{12 x }{5}$

$QD =\sqrt{( PQ )^2-( PQ )^2}=\sqrt{9 x ^2-\frac{144 x ^2}{25}}=\frac{9 x }{5}$

$	ext { and } DR =5 x -\frac{9 x }{5}=\frac{16 x }{5}$

Magnetic field at $P$ due to current elements $P Q$ and $P R$ is zero as the point $P$ is on the conductor. Therefore, magnetic field at $P$ due to current element $QR$ is

$B=\frac{\mu_0 I }{4 \pi PD }\left(\sin \phi_1+\sin \phi_2ight)$

$B =\frac{\mu_0 I 	imes 5}{4 \pi 	imes 12 x }\left(\frac{(9 x / 5)}{3 x }+\frac{(16 x / 5)}{4 x }ight)$

$B =\frac{\mu_0 I }{48 \pi x }\left(\frac{3}{5}+\frac{4}{5}ight)$

$B =\frac{7 \mu_0 I }{48 \pi x } \cdot k =7$

Similar Questions

A coil having ${N}$ turns is wound tightly in the form of a spiral with inner and outer radii $'a'$ and $'b'$ respectively. Find the magnetic field at centre, when a current $I$ passes through coil :

The radius of a circular current carrying coil is $R$. At what distance from the centre of the coil on its axis, the intensity of magnetic field will be $\frac{1}{2 \sqrt{2}}$ times that at the centre?

Current is flowing through a conducting hollow pipe whose area of cross-section is shown in the figure. The value of magnetic induction will be zero at

A current of $0.1\, A$ circulates around a coil of $100$ $turns$ and having a radius equal to $5\,cm$. The magnetic field set up at the centre of the coil is ($\mu_0 = 4\pi \times 10^{-7} weber/amp-metre$)

A thin circular frame of radius $'a'$ is made of insulating material. A square loop is constructed with in it. If loop carrying current $I$ , then magnetic induction at geometrical centre $'O'$ will be