A current of 0.1, A circulates around a coil | vedclass

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Question

(d) $B = \frac{{{\mu _0}}}{{4\pi }}.\frac{{2\pi Ni}}{r} = \frac{{{{10}^{ - 7}} 	imes 2\pi 	imes 100 	imes 0.1}}{{5 	imes {{10}^{ - 2}}}} = 4\pi

Vedclass · Accepted Answer

$4\pi 	imes 10^{-5} \,Tesla$

Vedclass · Answer

(d) $B = \frac{{{\mu _0}}}{{4\pi }}.\frac{{2\pi Ni}}{r} = \frac{{{{10}^{ - 7}} 	imes 2\pi 	imes 100 	imes 0.1}}{{5 	imes {{10}^{ - 2}}}} = 4\pi 	imes {10^{ - 5}}\,T$

A current of $0.1\, A$ circulates around a coil of $100$ $turns$ and having a radius equal to $5\,cm$. The magnetic field set up at the centre of the coil is ($\mu_0 = 4\pi \times 10^{-7} weber/amp-metre$)

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