The radius of a circular current carrying coi | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(c)

$\frac{\mu_0 i R^2}{2\left(R^2+x^2\right)^{3 / 2}}=\frac{1}{2 \sqrt{2}} \frac{\mu_0 i}{2 R}$

$2 \sqrt{2} R^3=\left(R^2+x^2\right)^{3 / 2}$

Vedclass · Accepted Answer

$R$

Vedclass · Answer

(c)

$\frac{\mu_0 i R^2}{2\left(R^2+x^2\right)^{3 / 2}}=\frac{1}{2 \sqrt{2}} \frac{\mu_0 i}{2 R}$

$2 \sqrt{2} R^3=\left(R^2+x^2\right)^{3 / 2}$

$(2 \sqrt{2})^{2 / 3} R^2=R^2+x^2$

$x^2=2 R^2-R^2=R^2 \Rightarrow x=R$

The radius of a circular current carrying coil is $R$. At what distance from the centre of the coil on its axis, the intensity of magnetic field will be $\frac{1}{2 \sqrt{2}}$ times that at the centre?

Similar Questions

Discuss special cases of Biot-Savart law.

Write equation of magnetic field due to a circular current carrying loop at a point on the axis of the loop. Give its special cases.

The magnetic induction at the centre $O$ of the current carrying bent wire shown in the adjoining figure is

A very long conducting wire is bent in a semicircular shape from $A$ to $B$ as shown in figure. The magnetic field at point $P$ for steady current configuration is given by:

In the hydrogen atom, the electron is making $6.6 \times {10^{15}}\,r.p.s.$ If the radius of the orbit is $0.53 \times {10^{ - 10}}\,metre,$ then magnetic field produced at the centre of the orbit is......$Tesla$