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(D) According to Ampere's Circuital Law,the magnetic field $B$ at a point is given by $\oint B \cdot dl = \mu_0 I_{enclosed}$.$1$. At point $P$,which

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$P$ but not at $Q$ and $R$

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(D) According to Ampere's Circuital Law,the magnetic field $B$ at a point is given by $\oint B \cdot dl = \mu_0 I_{enclosed}$.$1$. At point $P$,which is inside the hollow cavity of the pipe,the enclosed current $I_{enclosed} = 0$. Therefore,the magnetic field $B = 0$.$2$. At point $Q$,which is inside the material of the conducting pipe,the enclosed current $I_{enclosed}$ is non-zero because some current flows through the cross-sectional area inside the Amperian loop passing through $Q$. Therefore,$B 
eq 0$.$3$. At point $R$,which is outside the pipe,the total current enclosed by an Amperian loop passing through $R$ is the total current $I$ flowing through the pipe. Since the current is non-zero,the magnetic field $B 
eq 0$.Thus,the magnetic induction is zero only at point $P$.

Current is flowing through a conducting hollow pipe whose cross-section is shown in the figure. The value of magnetic induction will be zero at

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