A spherical capacitor has an inner sphere of radius $12 \;cm$ and an outer sphere of radius $13\; cm .$ The outer sphere is earthed and the inner sphere is given a charge of $2.5\; \mu \,C .$ The space between the concentric spheres is filled with a liquid of dielectric constant $32$
$(a)$ Determine the capacitance of the capacitor.
$(b)$ What is the potential of the inner sphere?
$(c)$ Compare the capacitance of this capacitor with that of an isolated sphere of radius $12 \;cm .$ Explain why the latter is much smaller.
Radius of the inner sphere, $r_{2}=12 \,cm =0.12\, m$
Radius of the outer sphere, $r_{1}=13 \,cm =0.13 m$
Charge on the inner sphere, $q=2.5\, \mu\, C=2.5 \times 10^{-6}\, C$
Dielectric constant of a liquid, $\epsilon_{r}=32$
$(a)$ Capacitance of the capacitor is given by the relation,
$C=\frac{4 \pi \epsilon_{0} \epsilon_{r} r_{1} r_{2}}{r_{1}-r_{2}}$ Where,
$\epsilon_{0}=$ Permittivity of free space $=8.85 \times 10^{-12} \,C ^{2} \,N ^{-1} \,m ^{-2}$
$\frac{1}{4 \pi \epsilon_{0}}=9 \times 10^{9} \,N\, m ^{2}\, C ^{-2}$
$\therefore C=\frac{32 \times 0.12 \times 0.13}{9 \times 10^{9} \times(0.13-0.12)}$
$=5.5 \times 10^{-9}\, F$
Hence, the capacitance of the capacitor is approximately $5.5 \times 10^{-9} \,F$
$(b)$ Potential of the inner sphere is given by,
$V=\frac{q}{C}$
$=\frac{2.5 \times 10^{-6}}{5.5 \times 10^{-9}}=4.5 \times 10^{2} \,V$
Hence, the potential of the inner sphere is $4.5 \times 10^{2} \,V$
$(c)$ Radius of an isolated sphere, $r=12 \times 10^{-2} \,m$
Capacitance of the sphere is given by the relation, $C^{\prime}=4 \pi \in_{0} r$
$=4 \pi \times 8.85 \times 10^{-12} \times 12 \times 10^{-12}$
$=1.33 \times 10^{-11} \,F$
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