બંધુકમાથી એક ગોળીને પ્રારંભિક વેગ u થી છોડતા | vedclass

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Question

$\begin{array}{l} Range\,will\,be\,same\,for\,time\,{t_1}\,and\,{t_2},\,so\,\ angles\,of\,projrection\,will\,be\,'	heta '\,\& '{90^

Vedclass · Accepted Answer

$2R/g$

Vedclass · Answer

$\begin{array}{l} Range\,will\,be\,same\,for\,time\,{t_1}\,and\,{t_2},\,so\,\ angles\,of\,projrection\,will\,be\,'	heta '\,\& '{90^ \circ } - 	heta '\ {t_1} = \frac{{2u\,\sin \,	heta }}{g}{t_2} = \frac{{2u\,\sin \,\left( {{{90}^ \circ } - 	heta } ight)}}{g}\,and\ \,\,\,\,\,\,\,R = \,\frac{{{u^2}\sin \,2	heta }}{g}\ {t_1}{t_2} = \frac{{4{u^2}\sin 	heta \cos 	heta }}{{{g^2}}} = \frac{2}{g}\left[ {\frac{{2{u^2}\sin 	heta \cos 	heta }}{g}} ight]\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = \frac{{2R}}{g} \end{array}$

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