A reaction involving two different reactants
Can never be a second order reaction
Can never be a unimolecular reaction
Can never be a bimolecular reaction
Can never be a first order reaction
$2 NO ( g )+ Cl _{2}( g ) \rightleftharpoons 2 NOCl ( s )$
This reaction was studied at $-10^{\circ} C$ and the following data was obtained
run | $[ NO ]_{0}$ | $\left[ Cl _{2}\right]_{0}$ | $r _{0}$ |
$1$ | $0.10$ | $0.10$ | $0.18$ |
$2$ | $0.10$ | $0.20$ | $0.35$ |
$3$ | $0.20$ | $0.20$ | $1.40$ |
$[ NO ]_{0}$ and $\left[ Cl _{2}\right]_{0}$ are the initial concentrations and $r _{0}$ is the initial reaction rate.
The overall order of the reaction is ..........
(Round off to the Nearest Integer).
Write general reaction. Write rate law of general reaction.
Consider the following data for the given reaction $2 \mathrm{HI}_{(\mathrm{g})} \rightarrow \mathrm{H}_{2(\mathrm{~g})}+\mathrm{I}_{2(\mathrm{~g})}$ . The order of the reaction is................
$1$ | $2$ | $3$ | |
$\mathrm{HI}\left(\mathrm{mol} \mathrm{L}^{-1}\right)$ | $0.005$ | $0.01$ | $0.02$ |
Rate $\left(\mathrm{mol} \mathrm{L}^{-1} \mathrm{~s}-1\right)$ | $7.5 \times 10^{-4}$ | $3.0 \times 10^{-3}$ | $1.2 \times 10^{-2}$ |
The alkaline hydrolysis of ethyl acetate is represented by the equation$C{H_3}COO{C_2}{H_5} + NaOH \to C{H_3}COONa + {C_2}{H_5}OH$ Experimentally it is found that for this reaction$\frac{{dx}}{{dt}} = k[C{H_3}COO{C_2}{H_5}]\,[NaOH]$ Then the reaction is
The rate constant for the reaction, $2{N_2}{O_5} \to 4N{O_2}$ $ + {O_2}$ is $3 \times {10^{ - 5}}{\sec ^{ - 1}}$. If the rate is $2.40 \times {10^{ - 5}}\,mol\,\,litr{e^{{\rm{ - 1}}}}{\sec ^{ - 1}}$. Then the concentration of ${N_2}{O_5}$ (in mol litre $^{-1}$) is