A positive charge particle of 100 ,mg is thro | vedclass

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(D) Given:Mass $m = 100 \,mg = 100 	imes 10^{-6} \,kg = 10^{-4} \,kg$Electric field $E = 1 	imes 10^{5} \,NC^{-1}$Charge $q = 40 \,\mu C = 40 	imes

Vedclass · Accepted Answer

$0.5$

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(D) Given:Mass $m = 100 \,mg = 100 	imes 10^{-6} \,kg = 10^{-4} \,kg$Electric field $E = 1 	imes 10^{5} \,NC^{-1}$Charge $q = 40 \,\mu C = 40 	imes 10^{-6} \,C$Initial velocity $u = 200 \,ms^{-1}$Final velocity $v = 0 \,ms^{-1}$The force acting on the particle is $F = qE$,which acts in the direction of the field. Since the particle is thrown in the opposite direction,the acceleration $a$ is negative:$a = -\frac{F}{m} = -\frac{qE}{m}$Using the kinematic equation $v^{2} = u^{2} + 2as$,where $v = 0$:$0 = u^{2} - 2 \left( \frac{qE}{m} ight) s$$s = \frac{u^{2}m}{2qE}$Substituting the values:$s = \frac{(200)^{2} 	imes 10^{-4}}{2 	imes 40 	imes 10^{-6} 	imes 10^{5}}$$s = \frac{40000 	imes 10^{-4}}{80 	imes 10^{-1}}$$s = \frac{4}{8} = 0.5 \,m$

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