A point charge of +12 ,mu C is at a distance | vedclass

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(C) The charge is placed at a distance $a/2 = 6 \,cm$ from the center of a square of side $a = 12 \,cm$. By considering the square as one face of a cu

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$226$

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(C) The charge is placed at a distance $a/2 = 6 \,cm$ from the center of a square of side $a = 12 \,cm$. By considering the square as one face of a cube of side $a = 12 \,cm$,the charge is at the center of this cube. According to Gauss's Law,the total electric flux through the entire cube is $\phi_{total} = \frac{q}{\varepsilon_{0}}$. Since the cube has $6$ identical faces,the flux through one face (the square) is $\phi = \frac{1}{6} \frac{q}{\varepsilon_{0}}$. Given $q = 12 	imes 10^{-6} \,C$ and $\varepsilon_{0} = 8.854 	imes 10^{-12} \,C^{2}/Nm^{2}$. $\phi = \frac{12 	imes 10^{-6}}{6 	imes 8.854 	imes 10^{-12}} = \frac{2 	imes 10^{-6}}{8.854 	imes 10^{-12}} \approx 0.2259 	imes 10^{6} \,Nm^{2}/C$. $\phi \approx 226 	imes 10^{3} \,Nm^{2}/C$.

$A$ point charge of $+12 \,\mu C$ is at a distance $6 \,cm$ vertically above the centre of a square of side $12 \,cm$ as shown in the figure. The magnitude of the electric flux through the square will be ....... $\times 10^{3} \,Nm^{2}/C$.

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