A physical quantity X is given by X = frac{2k | vedclass

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(C) The given physical quantity is $X = \frac{2k^3l^2}{m\sqrt{n}}$.The relative error in $X$ is given by the formula: $\frac{\Delta X}{X} = 3\frac{\De

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$12$

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(C) The given physical quantity is $X = \frac{2k^3l^2}{m\sqrt{n}}$.The relative error in $X$ is given by the formula: $\frac{\Delta X}{X} = 3\frac{\Delta k}{k} + 2\frac{\Delta l}{l} + \frac{\Delta m}{m} + \frac{1}{2}\frac{\Delta n}{n}$.Given percentage errors are $\frac{\Delta k}{k} 	imes 100 = 1\%$,$\frac{\Delta l}{l} 	imes 100 = 2\%$,$\frac{\Delta m}{m} 	imes 100 = 3\%$,and $\frac{\Delta n}{n} 	imes 100 = 4\%$.Substituting these values into the expression for percentage error:$\frac{\Delta X}{X} 	imes 100 = 3(1\%) + 2(2\%) + 3\% + \frac{1}{2}(4\%)$.Calculating the result: $3 + 4 + 3 + 2 = 12\%$.Therefore,the value of $X$ is uncertain by $12\%$.

$A$ physical quantity $X$ is given by $X = \frac{2k^3l^2}{m\sqrt{n}}$. The percentage errors in the measurements of $k, l, m$ and $n$ are $1\%, 2\%, 3\%$ and $4\%$ respectively. The value of $X$ is uncertain by .......... $\%$

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