A particle moves towards east with velocity 5 | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(b) $\Delta v = 2v\sin \left( {\frac{	heta }{2}} ight) = 2 	imes 5 	imes \sin 45^\circ $=$\frac{{10}}{{\sqrt 2 }}$

$&rArr;$  $a = \f

Vedclass · Accepted Answer

$\frac{1}{{\sqrt 2 }}\,m/{s^2}\,N - W$

Vedclass · Answer

(b) $\Delta v = 2v\sin \left( {\frac{	heta }{2}} ight) = 2 	imes 5 	imes \sin 45^\circ $=$\frac{{10}}{{\sqrt 2 }}$

$&rArr;$  $a = \frac{{\Delta v}}{{\Delta t}} = \frac{{10/\sqrt 2 }}{{10}} = \frac{1}{{\sqrt 2 }}\;m/{s^2}$

A particle moves towards east with velocity $5\, m/s$. After $10$ seconds its direction changes towards north with same velocity. The average acceleration of the particle is

Similar Questions

The potition $x$ of particle veries with time $t$ as $x = ct^2 + b,$ where $c, b$ are positive constant. Which of the following graph $s$ is correct

A body starts from the origin and moves along the $X-$axis such that the velocity at any instant is given by $(4{t^3} - 2t)$, where $t$ is in sec and velocity in$m/s$. What is the acceleration of the particle, when it is $2\, m$ from the origin..........$m/{s^2}$

Mark the correct statements for a particle going on a straight line

The acceleration-time graph of a body is shown below The most probable velocity-time graph of the body is

The displacement $(x)$ - time $(t)$ graph of a particle is shown in figure. Which of the following is correct?