The displacement $(x)$ - time $(t)$ graph of a particle is shown in figure. Which of the following is correct?
Particle starts with zero velocity and variable acceleration
Particle starts with non-zero velocity and variable acceleration
Particle starts with zero velocity and uniform acceleration
Particle starts with non-zero velocity and uniform acceleration
If the velocity of a particle is given by $v = {(180 - 16x)^{1/2}} m/s$, then its acceleration will be.......$ms^{-2}$
A particle moves a distance $x$ in time $t$ according to equation $x = (t + 5)^{-1}$ The acceleration of particle is proportional to
Draw $x \to t$ graph for positive acceleration.