The displacement (x) - time (t) graph of a pa | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The slope of the displacement-time graph represents the velocity of the particle,i.e.,$v = \frac{dx}{dt}$.At $t = 0$,the graph starts from the ori

Vedclass · Accepted Answer

Particle starts with zero velocity and variable acceleration

Vedclass · Answer

(A) The slope of the displacement-time graph represents the velocity of the particle,i.e.,$v = \frac{dx}{dt}$.At $t = 0$,the graph starts from the origin $(0, 0)$ and the tangent to the curve at the origin is horizontal (parallel to the $t$-axis).Since the slope of the tangent at $t = 0$ is zero,the initial velocity of the particle is zero.As time increases,the slope of the curve changes continuously,which implies that the velocity is changing with time.Since the velocity is changing with time,the particle is undergoing acceleration.Because the slope (velocity) is not changing at a constant rate (the curvature of the graph is not parabolic),the acceleration is variable.Therefore,the particle starts with zero velocity and variable acceleration.

The displacement $(x)$ - time $(t)$ graph of a particle is shown in the figure. Which of the following is correct?

Similar Questions

The figure shows the position of a particle moving on the $x$-axis as a function of time.

The following figures show velocity $v$ versus time $t$ curves. But only some of these can be realized in a particle. These are:

The graph of displacement $s$ versus time $t$ is given below. Its corresponding velocity-time graph will be:

What is common in the two graphs given below?

The given graph shows the variation of velocity $(v)$ with position $(x)$ for a particle moving along a straight line. Which of the following graphs shows the variation of acceleration $(a)$ with position $(x)$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module