A particle moves along $X-$axis as $x = 4(t - 2) + a{(t - 2)^2}$ Which of the following is true ?

  • A
    The initial velocity of particle is $4$
  • B
    The acceleration of particle is $2a$
  • C
    The particle is at origin at $t = 0$
  • D
    None of these

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A particle moves along a straight line. Its position at any instant is given by $x=32 t-\frac{8 t^3}{3}$, where $x$ is in metre and $t$ is in second. Find the acceleration of the particle at the instant when particle is at rest $..........\,m / s ^2$

A particle moves in a straight line so that its displacement $x$ at any time $t$ is given by $x^2=1+t^2$. Its acceleration at any time $\mathrm{t}$ is $\mathrm{x}^{-\mathrm{n}}$ where $\mathrm{n}=$ . . . . .

  • [JEE MAIN 2024]

What determines the nature of the path followed by the particle

Acceleration-time graph for a particle is given in figure. If it starts motion at $t=0$, distance travelled in $3 \,s$ will be ........... $m$

Velocity of a particle is in negative direction with constant acceleration in positive direction. Then, match the following columns.

Colum $I$ Colum $II$
$(A)$ Velocity-time graph $(p)$ Slope $\rightarrow$ negative
$(B)$ Acceleration-time graph $(q)$ Slope $\rightarrow$ positive
$(C)$ Displacement-time graph $(r)$ Slope $\rightarrow$ zero
  $(s)$ $\mid$ Slope $\mid \rightarrow$ increasing
  $(t)$ $\mid$ Slope $\mid$ $\rightarrow$ decreasing
  $(u)$ |Slope| $\rightarrow$ constant