A particle moves in a straight line so that its displacement $x$ at any time $t$ is given by $x^2=1+t^2$. Its acceleration at any time $\mathrm{t}$ is $\mathrm{x}^{-\mathrm{n}}$ where $\mathrm{n}=$ . . . . .
A particle moves in a straight line so that its displacement $x$ at any time $t$ is given by $x^2=1+t^2$. Its acceleration at any time $\mathrm{t}$ is $\mathrm{x}^{-\mathrm{n}}$ where $\mathrm{n}=$ . . . . .
- [JEE MAIN 2024]
- A
$5$
- B
$2$
- C
$3$
- D
$1$
Similar Questions
The area under acceleration-time graph gives
The area under acceleration-time graph gives
Suggest a suitable physical situation for following graphs.
Suggest a suitable physical situation for following graphs.
When acceleration and average acceleration are equal for moving object ?
When acceleration and average acceleration are equal for moving object ?
Refer to the graph in figure. Match the following
Velocity of a particle is in negative direction with constant acceleration in positive direction. Then, match the following columns.
Colum $I$
Colum $II$
$(A)$ Velocity-time graph
$(p)$ Slope $\rightarrow$ negative
$(B)$ Acceleration-time graph
$(q)$ Slope $\rightarrow$ positive
$(C)$ Displacement-time graph
$(r)$ Slope $\rightarrow$ zero
$(s)$ $\mid$ Slope $\mid \rightarrow$ increasing
$(t)$ $\mid$ Slope $\mid$ $\rightarrow$ decreasing
$(u)$ |Slope| $\rightarrow$ constant
Velocity of a particle is in negative direction with constant acceleration in positive direction. Then, match the following columns.
| Colum $I$ | Colum $II$ |
| $(A)$ Velocity-time graph | $(p)$ Slope $\rightarrow$ negative |
| $(B)$ Acceleration-time graph | $(q)$ Slope $\rightarrow$ positive |
| $(C)$ Displacement-time graph | $(r)$ Slope $\rightarrow$ zero |
| $(s)$ $\mid$ Slope $\mid \rightarrow$ increasing | |
| $(t)$ $\mid$ Slope $\mid$ $\rightarrow$ decreasing | |
| $(u)$ |Slope| $\rightarrow$ constant |