$A$ parallel plate capacitor is made of two plates of length $l$,width $w$ and separated by distance $d$. $A$ dielectric slab (dielectric constant $K$) that fits exactly between the plates is held near the edge of the plates. It is pulled into the capacitor by a force $F = -\frac{\partial U}{\partial x}$ where $U$ is the energy of the capacitor when the dielectric is inside the capacitor up to distance $x$ (See figure). If the charge on the capacitor is $Q$,then the force on the dielectric when it is near the edge is

  • A
    $\frac{{{Q^2}d}}{{2w{l^2}{\varepsilon _0}}}K$
  • B
    $\frac{{{Q^2}w}}{{2d{l^2}{\varepsilon _0}}}\left( {K - 1} \right)$
  • C
    $\frac{{{Q^2}d}}{{2w{l^2}{\varepsilon _0}}}\left( {K - 1} \right)$
  • D
    $\frac{{{Q^2}w}}{{2d{l^2}{\varepsilon _0}}}K$

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In the figure,a capacitor is filled with dielectrics. The resultant capacitance is

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