What will be the capacity of a parallel-plate capacitor when the half of the parallel space between the plates is filled by a material of dielectric constant $\varepsilon_r$? Assume that the capacity of the capacitor in air is $C$.

  • A
    $\frac{2\varepsilon_r C}{1 + \varepsilon_r}$
  • B
    $\frac{C(\varepsilon_r + 1)}{2}$
  • C
    $\frac{\varepsilon_r C}{1 + \varepsilon_r}$
  • D
    $\varepsilon_r C$

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The plates of a parallel plate capacitor are charged up to $100 \,V$. $A$ $2 \,mm$ thick insulator sheet is inserted between the plates. Then, to maintain the same potential difference, the distance between the plates is increased by $1.6 \,mm$. The dielectric constant of the insulator is

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