A nuclear reaction is given by

{}_Z{X^A} t | vedclass

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Question

${}_{ - 1}{e^0}$ is known as ${\beta ^ - }$particle and $\bar v$ is known as antineutrino. Since in this reaction $\bar v$ is emitted with ${}_{ - 1}{

Vedclass · Accepted Answer

$\beta  - $ decay

Vedclass · Answer

${}_{ - 1}{e^0}$ is known as ${\beta ^ - }$particle and $\bar v$ is known as antineutrino. Since in this reaction $\bar v$ is emitted with ${}_{ - 1}{e^0}$ (${\beta ^ - }$ particle or electron), so it is known as $\beta  - $ decay

A nuclear reaction is given by

${}_Z{X^A} \to {}_{Z + 1}{Y^A} + {}_{ - 1}{e^0} + \bar v$ , represents

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A nuclear reaction is given by ${}_Z{X^A} \to {}_{Z + 1}{Y^A} + {}_{ - 1}{e^0} + \bar v$ , represents