A certain stable nucleide, after absorbing a neutron, emits $\beta$-particle and the new nucleide splits spontaneously into two $\alpha$-particles. The nucleide is
A certain stable nucleide, after absorbing a neutron, emits $\beta$-particle and the new nucleide splits spontaneously into two $\alpha$-particles. The nucleide is
- A
${ }_2^4 He$
- B
${ }_3^7 Li$
- C
${ }_4^6 Be$
- D
${ }_3^6 Li$
Similar Questions
A nucleus of an element ${}_{84}{X^{202}}$ emits an $\alpha $-particle first, $\beta $ -particle next and then a gamma photon. The final nucleus formed has an atomic number
A nucleus of an element ${}_{84}{X^{202}}$ emits an $\alpha $-particle first, $\beta $ -particle next and then a gamma photon. The final nucleus formed has an atomic number
In the equation ${ }_{13}^{27} Al +{ }_2^4 He \longrightarrow{ }_{15}^{30} P + X ,$ The correct symbol for $X$ is
In the equation ${ }_{13}^{27} Al +{ }_2^4 He \longrightarrow{ }_{15}^{30} P + X ,$ The correct symbol for $X$ is
For the given reaction, the particle $X$ is $_6{C^{11}}{ \to _5}{B^{11}} + {\beta ^ + } + X$
For the given reaction, the particle $X$ is $_6{C^{11}}{ \to _5}{B^{11}} + {\beta ^ + } + X$
- [AIPMT 2000]
If $_{92}{U^{238}}$ undergoes successively $8 \alpha$- decays and $6 \beta$- decays, then resulting nucleus is
If $_{92}{U^{238}}$ undergoes successively $8 \alpha$- decays and $6 \beta$- decays, then resulting nucleus is
- [AIIMS 1996]
After one $\alpha $ and two $\beta $ emissions
After one $\alpha $ and two $\beta $ emissions
- [AIPMT 1999]