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(B) The distance between the Sun and the Earth is given by the product of the speed of light and the time taken by light to travel this distance.Given

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$500$

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(B) The distance between the Sun and the Earth is given by the product of the speed of light and the time taken by light to travel this distance.Given that in the new unit system,the speed of light $c = 1 \; 	ext{unit/s}$.The time taken by light to travel from the Sun to the Earth is $t = 8 \; 	ext{min} \; 20 \; 	ext{s}$.Converting the time into seconds: $t = (8 	imes 60) \; 	ext{s} + 20 \; 	ext{s} = 480 \; 	ext{s} + 20 \; 	ext{s} = 500 \; 	ext{s}$.Therefore,the distance $d = c 	imes t = 1 	imes 500 = 500 \; 	ext{units}$.

$A$ new unit of length is chosen such that the speed of light in vacuum is unity. What is the distance between the Sun and the Earth in terms of the new unit if light takes $8 \; min$ and $20 \; s$ to cover this distance?

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