A force of 5, N acts on a particle along a di | vedclass

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(D) The component of a vector $\vec{F}$ making an angle $	heta$ with a specific axis is given by $F \cos 	heta$ along that axis.Here,the force $F =

Vedclass · Accepted Answer

$2.5$

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(D) The component of a vector $\vec{F}$ making an angle $	heta$ with a specific axis is given by $F \cos 	heta$ along that axis.Here,the force $F = 5\, N$ makes an angle $	heta = 60^\circ$ with the vertical axis.Therefore,the vertical component of the force is $F_v = F \cos 60^\circ$.Substituting the values,we get $F_v = 5 	imes \frac{1}{2} = 2.5\, N$.Thus,the vertical component is $2.5\, N$.

$A$ force of $5\, N$ acts on a particle along a direction making an angle of $60^\circ$ with the vertical. Its vertical component is.......$N$.

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