A die is thrown, find the probability of following events: A number less than or equal to one will appear,
The sample space of the given experiment is given by
$S=\{1,2,3,4,5,6\}$
Let $C$ be the event of the occurrence of a number less than or equal to one.
Accordingly, $C\{1\}$
$\therefore P(C)=\frac{\text { Number of outcomes favourable to } C}{\text { Total number of possible outcomes }}=\frac{n(C)}{n(S)}=\frac{1}{6}$
A box contains $2$ black, $4$ white and $3$ red balls. One ball is drawn at random from the box and kept aside. From the remaining balls in the box, another ball is drawn at random and kept aside the first. This process is repeated till all the balls are drawn from the box. The probability that the balls drawn are in the sequence of $2$ black, $4$ white and $3$ red is
Three identical dice are rolled. The probability that same number will appear on each of them will be
$A$ and $B$ are two independent events such that $P(A) = \frac{1}{2}$ and $P(B) = \frac{1}{3}$. Then $P$ (neither $A$ nor $B$) is equal to
A box contains $1$ red and $3$ identical white balls. Two balls are drawn at random in succession without replacement. Write the sample space for this experiment.
The probability that a marksman will hit a target is given as $1/5$. Then his probability of at least one hit in $10$ shots, is