$A$ die is thrown. Find the probability of the following event: $A$ number less than or equal to $1$ will appear.

What is the probability of getting a doublet when two dice are thrown?

$A$ number $x$ is chosen at random from the set $\{1, 2, 3, 4, ......, 100\}$. Then the probability of the event that the chosen number $x$ satisfies the inequality $\frac{(x - 10)(x - 50)}{(x - 30)} \geqslant 0$ is:

Given $P(A \cup B)=0.6$ and $P(A \cap B)=0.2$,the probability that exactly one of the events occurs is:

$A$ coin is tossed twice. The probability of getting head both the times is

When a pair of six-faced fair dice are thrown,the probability that the sum of the numbers on the two dice is greater than $7$ is: