A die is loaded in such a way that each odd number is twice as likely to occur as each even number. If $E$ is the event that a number greater than or equal to $4$ occurs on a single toss of the die then $P(E)$ is equal to

  • A

    $\frac{4}{9}$

  • B

    $\frac{2}{3}$

  • C

    $\frac{1}{3}$

  • D

    $\frac{1}{2}$

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