$A$ current loop $ABCD$ is held fixed on the plane of the paper as shown in the figure. The arcs $BC$ (radius $= b$) and $DA$ (radius $= a$) of the loop are joined by two straight wires $AB$ and $CD$. $A$ steady current $I$ is flowing in the loop. The angle made by $AB$ and $CD$ at the origin $O$ is $30^\circ$. Another straight thin wire with steady current $I_1$ flowing out of the plane of the paper is kept at the origin. The magnitude of the magnetic field $(B)$ due to the loop $ABCD$ at the origin $(O)$ is:

  • A
    $0$
  • B
    $\frac{{\mu _0}I(b - a)}{{24ab}}$
  • C
    $\frac{{\mu _0}I}{{4\pi }}\left[ {\frac{{b - a}}{{ab}}} \right]$
  • D
    $\frac{{\mu _0}I}{{4\pi }}\left[ {2(b - a) + \frac{{\pi (a + b)}}{3}} \right]$

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Similar Questions

When a certain length of wire is turned into one circular loop,the magnetic induction at the centre of the coil due to a current $I$ flowing through it is $B_1$. If the same wire is turned into three loops to make a circular coil,the magnetic induction at the center of this coil for the same current will be:

Two concentric coils each of radius equal to $2\pi \text{ cm}$ are placed at right angles to each other. If $3 \text{ A}$ and $4 \text{ A}$ are the currents flowing through the two coils respectively,the magnetic induction (in $\text{Wb m}^{-2}$) at the centre of the coils will be:

Which law is useful to determine the relation between current and the magnetic field produced by it?

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Which of the following figures correctly depicts the direction of the magnetic field of a current-carrying coil?

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